The length of the side of an equilateral triangle inscribed in the parabola, `y^2=4x` so that one of its angular point is at the vertex is:
Text Solution
Verified by Experts
The correct Answer is:
`8asqrt3`
Topper's Solved these Questions
PARABOLA
FIITJEE|Exercise EXERCISE 3|4 Videos
PARABOLA
FIITJEE|Exercise EXERCISE 4|4 Videos
PARABOLA
FIITJEE|Exercise EXERCISE 1|6 Videos
MATRICES
FIITJEE|Exercise NUMERICAL BASED|3 Videos
PERMUTATIONS & COMBINATIONS
FIITJEE|Exercise NUMERICAL BASED|3 Videos
Similar Questions
Explore conceptually related problems
An equilateral triangle is inscribed in the parabola y^(2)=4ax, such that one vertex of this triangle coincides with the vertex of the parabola.Then find the side length of this triangle.
An equilateral triangle is inscribed in the parabola y^(2)=4ax whose vertex is at of the parabola.Find the length of its side.
What is the length of an equilateral triangle inscribed in the circle x^(2)+y^(2)=(4)/(3)?
The length of the side (in cm) of an equilateral triangle inscribed in a circle of radius 8 cm is ___________.
If an equilateral triangle is inscribed in the circle x^(2)+y2=a^(2), the length of its each side is
If 2,4,8 are the ordinates of the vertices of a triangle inscribed in the parabola y^(2)=8x ,then area of triangle is