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Prove that the straight lines x/a-y/b =m...

Prove that the straight lines `x/a-y/b =m and x/a+y/b=1/m,` where `a and b` are `'m'` is a parameter, always meet on agiven positive real numbers and hyperbola.

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The correct Answer is:
`x^(2)/(a^(2)) - y^(2)/b^(2) = 1 ` which is hyperbola
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