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Consider the curve C satisfying 2xydy = ...

Consider the curve C satisfying `2xydy = (x^(2) + y^(2) + 1) dx`
Statement 1 : Curve C represents a family of rectangular hyperbola with centre on x- axis and Statement 2 : Curve C represents a family of rectangular hyperbolas with centre on y - axis

A

Statement - 1 is True, Statement - 2 is True, Statement - 2 is a correct explanation for Statement - 2

B

Statement - 1 is True, Statement - 2 is True, Statement - 2 is NOT a correct explanation for Statement - 2

C

Statement - 1 is True , Statement - 2 is False

D

Statement - 1 is False, Statement - 2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem, we need to analyze the differential equation and determine the nature of the curve it represents. Let's go through the solution step by step. ### Step 1: Write the given differential equation The differential equation is given by: \[ 2xy \, dy = (x^2 + y^2 + 1) \, dx \] ### Step 2: Rearrange the equation We can rearrange the equation to isolate \( \frac{dy}{dx} \): \[ \frac{dy}{dx} = \frac{x^2 + y^2 + 1}{2xy} \] ### Step 3: Substitute \( y^2 \) with \( b \) Let’s substitute \( y^2 \) with \( b \): \[ b = y^2 \] Thus, \( dy = \frac{1}{2\sqrt{b}} db \). ### Step 4: Rewrite the equation using the substitution Substituting \( dy \) into the equation gives: \[ \frac{1}{2\sqrt{b}} \frac{db}{dx} = \frac{x^2 + b + 1}{2x\sqrt{b}} \] ### Step 5: Simplify the equation Multiplying through by \( 2x\sqrt{b} \) to eliminate the denominators results in: \[ x \, db = (x^2 + b + 1) \, dx \] ### Step 6: Rearranging terms Rearranging gives: \[ db - \frac{b}{x^2 + 1} \, dx = dx \] ### Step 7: Separate variables This can be separated as: \[ \frac{db}{b} = \frac{dx}{x} + \frac{dx}{x^2 + 1} \] ### Step 8: Integrate both sides Integrating both sides leads to: \[ \ln |b| = \ln |x| + \tan^{-1}(x) + C \] ### Step 9: Exponentiate to solve for \( b \) Exponentiating gives: \[ b = k \cdot x \cdot e^{\tan^{-1}(x)} \] where \( k = e^C \). ### Step 10: Substitute back for \( b \) Substituting back for \( b = y^2 \): \[ y^2 = k \cdot x \cdot e^{\tan^{-1}(x)} \] ### Step 11: Analyze the resulting equation The resulting equation represents a family of curves. To determine if they are hyperbolas, we analyze the behavior of the equation. ### Conclusion The curves represented by the equation are hyperbolas centered on the x-axis, confirming that Statement 1 is true and Statement 2 is false. ### Final Answer Thus, the correct answer is that Statement 1 is true and Statement 2 is false. ---
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