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The number of distinct straight lines th...

The number of distinct straight lines through the points of intersection of `x^(2) - y^(2) = 1" and " x^(2) + y^(2) - 4x - 5 = 0 `

A

0

B

1

C

2

D

3

Text Solution

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The correct Answer is:
To find the number of distinct straight lines through the points of intersection of the hyperbola \( x^2 - y^2 = 1 \) and the circle \( x^2 + y^2 - 4x - 5 = 0 \), we will follow these steps: ### Step 1: Find the points of intersection We need to solve the equations of the hyperbola and the circle simultaneously. 1. The equation of the hyperbola is: \[ x^2 - y^2 = 1 \tag{1} \] 2. The equation of the circle can be rearranged. First, we complete the square: \[ x^2 + y^2 - 4x - 5 = 0 \implies (x-2)^2 + y^2 = 9 \] This represents a circle with center \( (2, 0) \) and radius \( 3 \). ### Step 2: Substitute \( y^2 \) from the hyperbola into the circle's equation From equation (1), we can express \( y^2 \): \[ y^2 = x^2 - 1 \] Now, substitute \( y^2 \) into the circle's equation: \[ (x-2)^2 + (x^2 - 1) = 9 \] ### Step 3: Simplify and solve for \( x \) Expanding the equation: \[ (x-2)^2 + x^2 - 1 = 9 \] \[ (x^2 - 4x + 4) + x^2 - 1 = 9 \] Combine like terms: \[ 2x^2 - 4x + 3 = 9 \] \[ 2x^2 - 4x - 6 = 0 \] Divide the entire equation by 2: \[ x^2 - 2x - 3 = 0 \] ### Step 4: Factor the quadratic equation Factoring gives: \[ (x - 3)(x + 1) = 0 \] Thus, the solutions for \( x \) are: \[ x = 3 \quad \text{and} \quad x = -1 \] ### Step 5: Find corresponding \( y \) values Substituting \( x = 3 \) into \( y^2 = x^2 - 1 \): \[ y^2 = 3^2 - 1 = 9 - 1 = 8 \implies y = \pm 2\sqrt{2} \] So we have the points \( (3, 2\sqrt{2}) \) and \( (3, -2\sqrt{2}) \). Now substituting \( x = -1 \): \[ y^2 = (-1)^2 - 1 = 1 - 1 = 0 \implies y = 0 \] So we have the point \( (-1, 0) \). ### Step 6: Determine the number of distinct lines The points of intersection are: 1. \( (3, 2\sqrt{2}) \) 2. \( (3, -2\sqrt{2}) \) 3. \( (-1, 0) \) To find the number of distinct straight lines through these points: - From \( (3, 2\sqrt{2}) \) and \( (3, -2\sqrt{2}) \), we can draw a vertical line. - From \( (3, 2\sqrt{2}) \) and \( (-1, 0) \), we can draw a line. - From \( (3, -2\sqrt{2}) \) and \( (-1, 0) \), we can draw another line. Thus, we have a total of **three distinct lines**. ### Final Answer The number of distinct straight lines through the points of intersection is **3**. ---
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