The arc AC of a circle subtends a righe angle at the centre O B divides the arc in the ratio 5:1. If `barOA=bara and barOB=barb` then show that `bar(OC)=(2sqrt2b-(sqrt3-1)bara)/(sqrt3+1)`

An arc AC of a circle subtends a right angle at then the center O. the point B divides the are in the ratio 1:2, If vec OA=a&vec OB=b .then the vector vec OC in terms of a&b, is

If 2bara+barb=3barc, then A divides BC in the ratio

If the arc of the same length in two circles subtend angles 75^(@) and 120^(2) at the centre, find the ratio of their radii.

The position vectors of the point which divides internally in the ratio 2:3 the join of the points 2bara-3barb and 3bara-2barb , is

A chord of a circle of radius 10cm subtends a a right angle at the centre.The length of the chord (in cm) is 5sqrt(2)(b)10sqrt(2)(c)(5)/(sqrt(2)) (d) 10sqrt(3)

The angle subtended at the centre of a circle of radius 3 cm by an arc of lenhgth 1 cm is :

Find a and b when (sqrt3 -1)/(sqrt3 +1) +(sqrt3 +1)/(sqrt3 -1) = a+sqrt3 b

In a circle of radius 14 cm, an arc subtends an angle of 120^(@) at the centre. If sqrt(3)=1.73 then the area of the segment of the circle is

A triangle is inscribed in a circle.The vertices of the triangle divide the circle into three arcs of length 3,4 and 5 ,then the area of the triangle is equal to 1.(9sqrt(3)(1+sqrt(3)))/(pi^(2)) 2.(9sqrt(3)(sqrt(3)-1))/(pi^(2)) 3.(9sqrt(3)(1+sqrt(3)))/(2 pi^(2)) 4.(9sqrt(3)(sqrt(3)-1))/(2 pi^(2))