Potential in the x-y plane is given as `V=5(x^(2)+xy)` volts. Find the electric field at the point (1, -2).

Explanation

To solve the problem of finding the electric field at the point (1, -2) given the potential function \( V = 5(x^2 + xy) \), we will follow these steps:

### Step 1: Understand the relationship between electric field and potential
The electric field \( \mathbf{E} \) is related to the electric potential \( V \) by the equation:
\[ \mathbf{E} = -\nabla V \]
where \( \nabla V \) is the gradient of the potential. In two dimensions, this can be expressed as:
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