A conducting ball is given a certain charge and fixed at point P. An another point charge of mass 1 gm and charge `20muC` when kept at Q (3m, 9m) starts moving with acceleration `veca=(1.08hati+1.44hatj)ms^(-2)`. The potential at Q is `+720` volt. Calculate
(a) charge given to ball
(b) position of the ball.

Explanation

To solve the problem step by step, we need to calculate the charge given to the conducting ball and the position of the ball based on the provided information.

### Given Data:
- Mass of the point charge \( m = 1 \, \text{g} = 1 \times 10^{-3} \, \text{kg} \)
- Charge of the point charge \( Q_2 = 20 \, \mu\text{C} = 20 \times 10^{-6} \, \text{C} \)
- Position of point \( Q \) is \( (3 \, \text{m}, 9 \, \text{m}) \)
- Acceleration \( \vec{a} = (1.08 \hat{i} + 1.44 \hat{j}) \, \text{m/s}^2 \)
- Electric potential at \( Q \) is \( V = 720 \, \text{V} \)
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