A charge Q is divided into two parts. Charge on each part is q. Also, `Q//q=2`. What is the Columbic force between two charges q and q when both parts are placed certain distance apart?

Options

A. Force is equal in magnitude for both but opposite in direction
B. Force is dependent on the medium in which charges are placed
C. Force is maximum irrespective of medium in which charges are placed
D. None of the above

Answer

To solve the problem, we need to find the Coulombic force between two charges \( q \) and \( q \) when a charge \( Q \) is divided into two equal parts, where \( \frac{Q}{q} = 2 \).

### Step-by-Step Solution:

1. **Understanding the Charge Division**:
Given that \( Q \) is divided into two parts, and each part has a charge \( q \). From the ratio \( \frac{Q}{q} = 2 \), we can express \( Q \) in terms of \( q \):
\[ Q = 2q \]

2. **Identifying the Charges**:
Since \( Q \) is divided into two equal parts, we have:
\[ q_1 = q \quad \text{and} \quad q_2 = q \]

3. **Using Coulomb's Law**:
The formula for the Coulombic force \( F \) between two point charges \( q_1 \) and \( q_2 \) separated by a distance \( r \) is given by:
\[ F = k \frac{q_1 q_2}{r^2} \]
where \( k \) is Coulomb's constant, \( k = \frac{1}{4 \pi \epsilon_0} \).

4. **Substituting the Values**:
Substituting \( q_1 = q \) and \( q_2 = q \) into the formula, we get:
\[ F = k \frac{q \cdot q}{r^2} = k \frac{q^2}{r^2} \]

5. **Final Expression for the Force**:
Therefore, the Coulombic force between the two charges \( q \) and \( q \) is:
\[ F = k \frac{q^2}{r^2} \]

### Conclusion:
The Coulombic force between the two charges \( q \) and \( q \) when they are separated by a distance \( r \) is given by:
\[ F = k \frac{q^2}{r^2} \]