Statement-1: If the plates of a capacitor are connected through a conducting wire, then its capacitance becomes infinite.
Statement-2: The capacitors cannot be charged.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for statement-1
B. Statement-2 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False, Statement-2 is True.

Answer

To solve the question regarding the two statements about the capacitor, we will analyze each statement step by step.

### Step 1: Understanding Statement 1
**Statement 1:** If the plates of a capacitor are connected through a conducting wire, then its capacitance becomes infinite.

- A capacitor consists of two plates separated by a dielectric material. The capacitance \( C \) of a capacitor is defined as:
\[ C = \frac{Q}{V} \]
where \( Q \) is the charge on one plate and \( V \) is the potential difference between the plates.

- When we connect the two plates of the capacitor with a conducting wire, the potential difference \( V \) between the plates becomes zero because the wire allows charge to flow freely, equalizing the potential on both plates.

- Since \( V = 0 \), substituting this into the capacitance formula gives:
\[ C = \frac{Q}{0} \]
This expression suggests that capacitance \( C \) approaches infinity when \( V \) is zero, as long as there is some charge \( Q \) present.

### Conclusion for Statement 1:
- **Statement 1 is correct.** The capacitance becomes infinite when the plates are connected by a conducting wire.

### Step 2: Understanding Statement 2
**Statement 2:** The capacitors cannot be charged.

- Charging a capacitor requires a potential difference between the plates. When the plates are connected by a conducting wire, the potential difference \( V \) is zero, which means there is no driving force to move charges from one plate to another.

- The relationship between charge \( Q \), capacitance \( C \), and potential difference \( V \) is given by:
\[ Q = C \cdot V \]
If \( C \) is infinite (as established in Statement 1) and \( V \) is zero, then:
\[ Q = \infty \cdot 0 \]
This indicates that no charge can accumulate on the capacitor plates because the potential difference is zero.

### Conclusion for Statement 2:
- **Statement 2 is also correct.** The capacitor cannot be charged when the plates are connected by a conducting wire.

### Final Conclusion:
Both statements are correct, but Statement 2 does not specifically explain why capacitors cannot be charged in all situations. Therefore, while both statements are true, Statement 2 is not a suitable explanation for Statement 1.