[41x+53y=135-],[53x+41y=147]

Solve 41x + 53y = 135 and 53x + 41y = 147.

If [[2x,1],[5,x+2y]]=[[4,1],[5,0]] then find the value of x+y.

In Fig.74, if A B C D ,\ /_C A B=49^0, /_C B D=27^0\ a n d\ /_B C D=112^0, then the values of x\ a n d\ y are x=41 ,\ y=90 ,\ (b) x=41 ,\ y=63 , x=63 ,\ y=41 , (d) x=90 ,\ y=41 ,

In Fig.74, if A B C D ,\ /_C A B=49^0, /_C B D=27^0\ a n d\ /_B C D=112^0, then the values of x\ a n d\ y are x=41 ,\ y=90 ,\ (b) x=41 ,\ y=63 , x=63 ,\ y=41 , (d) x=90 ,\ y=41 ,

A ray of light is incident along a line which meets another line,7x-y+1=0, at the point (0,1). The ray isthen reflected from this point along the line,y+2x=1. Then the equation of the line of incidence of the ray of light is (A) 41x+38y-38=0 (B) 41x-38y+38=0( C) 41x+25y-25=0 (D) 41x-25y+25=0

A ray of light is incident along a line which meets another line, 7x-y+1 = 0 , at the point (0, 1). The ray isthen reflected from this point along the line, y+ 2x=1 . Then the equation of the line of incidence of the ray of light is (A) 41x + 38 y - 38 =0 (B) 41 x - 38 y + 38 = 0 (C) 41x + 25 y - 25 = 0 (D) 41x - 25y + 25 =0

If 53x-54y+7=0and 106x-108y=-4 are the tangents of the circle , then radius of the circle is =.......