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If (1+x)^(n) = C(0)+C(1)x + C(2) x^(2) +...

If `(1+x)^(n) = C_(0)+C_(1)x + C_(2) x^(2) +...+C_(n)x^(n)`
then ` C_(0)""^(2)+C_(1)""^(2) + C_(2)""^(2) +...+C_(n)""^(2)` is equal to

A

`2^(n-2)`

B

`2^(n)`

C

`(2n!)/(2(n!)^(2))`

D

`(2n!)/((n!)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
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