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(1)/(n!) +(1)/(2!(n-2)!) +(1)/(4!(n-4)!)...

`(1)/(n!) +(1)/(2!(n-2)!) +(1)/(4!(n-4)!) +...` is equal to

A

`(2^(n))/(n!)`

B

`(2^(n-2))/((n-1)!)`

C

`(2^(n-1))/((n-2)!)`

D

`(2^(n-1))/(n!)`

Text Solution

Verified by Experts

The correct Answer is:
D
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