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Two players P1a n dP2 play a series o...

Two players `P_1a n dP_2` play a series of `2n` games. Each game can result in either a win or a loss for `P_1dot` the total number of ways in which `P_1` can win the series of these games is equal to a. `1/2(2^(2n)-^^(2n)C_n)` b. `1/2(2^(2n)-2xx^^(2n)C_n)` c. `1/2(2^n-^^(2n)C_n)` d. `1/2(2^n-2xx^^(2n)C_n)`

A

`(1)/(3)(2^(2n)-2.""^(2n)C_(n))`

B

`(1)/(2)(2^(n)-2.""^(2n)C_(n))`

C

`(1)/(3)(2^(n)-""^(2n)C_(n))`

D

`(1)/(3)(2^(2n)-2.""^(2n)C_(n))`

Text Solution

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The correct Answer is:
D
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