" If "x=sec theta+tan theta," then "x+(1)/(x)=

If 3x=sec theta,(3)/(x) =tan theta then (x^(2)-(1)/(x^(2))) I equal to:

If sec theta+tan theta=x, then sec theta=(a)(x^(2)+1)/(x) (b) (x^(2)+1)/(2x)(c)(x^(2)-1)/(2x) (d) (x^(2)-1)/(x)

If sec theta+tan theta=x then sec theta=

If x= a ( sec theta + tan theta )^2 , y=b(sec theta - tan theta )^2 " then " x^(2) y^(2) =

If x=a(sec theta + tan theta)^(2) and y=b(sec theta- tan theta)^(4) , then x^(4)y^(2)=

if x = a sec theta + b tan theta y = b sec theta + a tan theta then x^(2) - y^(2) is equal to

If x=sec theta - tan theta, y = cosec theta + cot theta then prove that xy+x-y+1=0 .

If sec theta+tan theta=x, then tan theta=(x^(2)+1)/(x) (b) (x^(2)-1)/(x)( c) (x^(2)+1)/(2x) (d) (x^(2)-1)/(2x)

If 2x = sec theta and 2/x = tan theta , then 2(x^2 - (1)/(x^2)) =

If 4x = sec theta and 4/x = tan theta , then 8(x^2 -1/x^2) is