" 11."2+5+8+11+...+(3n-1)=(1)/(2)n(3n+1)

Prove by mathematical induction 5 + 8 + 11 + ...+ (3n-+2)= 1/2 n(3n + 7).

Prove the following by the principle of mathematical induction: 2+5+8+11++(3n-1)=(1)/(2)n(3n+1)

Prove by the principle of mathematical induction that 2+5+8+11+….+(3n-1)=1/2n(3n+1),AA n in N .

Prove the following by the principle of mathematical induction: 2+5+8+11++(3n-1)=1/2n\ (3n+1)

Prove that by using the principle of mathematical induction for all n in N : (1)/(2.5)+ (1)/(5.8) + (1)/(8.11)+ ...+(1)/((3n-1)(3n+2))= (n)/(6n+4)

Prove that by using the principle of mathematical induction for all n in N : (1)/(2.5)+ (1)/(5.8) + (1)/(8.11)+ ...+(1)/((3n-1)(3n+2))= (n)/(6n+4)

Prove the following by using the principle of mathematical induction for all n in N : 1/(2. 5)+1/(5. 8)+1/(8. 11)+...+1/((3n-1)(3n+2))=n/((6n+4))

Prove the following by using the principle of mathematical induction for all n in N :- 1/2.5+1/5.8+1/8.11+...+1/((3n-1)(3n+ 2))=n/((6n+ 4))

Using the mathematical induction, show that for any natural number n, 1/2.5 + 1/5.8 + 1/8.11 + …+ 1/((3n-1)(3n+2))=n/(6n+4)