[" Q2.The function "f:[0,oo)rarrquad 1" point "],[" R given by "f(x)=x/(x+1)" is "^(*)]

Prove that the function f: [0,oo)rarr R , given by f(x) =9x^(2) +6x -5 is not invertible. Modify the codomain of the functions to make it invertible, and hence find f^(-1)

If f:[1, oo)rarr[2, oo) is given by f(x)=x+(1)/(x) then f^(-1)(x)=

The function f:[0,oo] to R given by f(x)=(x)/(x+1) is

A function f:(0,oo)rarr[0,oo] is given by f(x)=|1-(1)/(x)|, then f(x) is (A) Injective but not surjective (B) Injective and bijective (C) Injective only (D) Surjective only

If the function f: [2, oo) rarr [-1, oo) is defined by f(x)=x^(2)-4x+3 then f^(-1)(x)=

If the function f:[2,oo)rarr[-1,oo) is defined by f(x)=x^(2)-4x+3 then f^(-1)(x)=

If f: [1, oo) rarr [5, oo) is given by f(x) = 3x + (2)/(x) , then f^(-1) (x) =

If the function f:[1, oo) rarr [ 1,oo) defined by f(x) = 2^(x(x -1)) is invertible, then find f^(-1) (x).

Show that the function f:R-{3}rarr R-{1} given by f(x)=(x-2)/(x-3) is bijection.

Let a function f:(1, oo)rarr(0, oo) be defined by f(x)=|1-(1)/(x)| . Then f is