Let `f(x)=ax^2-bx+c^2 != 0 and f(x) != 0` for all `x in R.` Then (a) `a^2+c^2 2` (b) `c` (c) `a-3b+c^2 < 0` (d) non of these

Let f(x) = ax^(2) - bx + c^(2), b ne 0 and f(x) ne 0 for all x in R . Then

If f(x) =ax^(2) + bx + c satisfies the identity f(x+1) -f(x)= 8x+ 3 for all x in R Then (a,b)=

Let f(x)=ax^(2)+bx+c, if a>0 then f(x) has minimum value at x=

Let f(x) is ax^(2)+bx+c;(3a+b>0) and f(x)>=0 AA x in R, then minimum value of (4a+2b+c)/(3a+b) is

Let f (x) =ax ^(2) + bx+ c,a gt = and f (2-x) =f (2+x) AA x in R and f (x) =0 has 2 distinct real roots, then which of the following is true ?

Let f(x)=ax^(2)+bx+c, if f(-1) -1,f(3)<-4 and a!=0 then

Let f (x) =ax ^(2) +bx + c,a ne 0, such the f (-1-x)=f (-1+ x) AA x in R. Also given that f (x) =0 has no real roots and 4a + b gt 0. Let alpha =4a -2b+c, beta =9a+3b+c, gamma =9a -3b+c, then which of the following is correct ?

Let f (x) =ax ^(2) +bx + c,a ne 0, such the f (-1-x)=f (-1+ x) AA x in R. Also given that f (x) =0 has no real roots and 4a + b gt 0. Let p =b-4a, q=2a +b, then pq is:

if f(x)=ax^2+bx+c, where f(0)=4,f(1)=3 and f(-1)=9, then: (a,b,c)-=