int[sin(log x)+cos(log x)]dx=

int sin(log x)dx

int cos(log x)dx

int sin(log x) dx=........ (A) (x/2)[sin(log x) - cos(log x)] + c (B) (x/2)[sin(log x) + cos(log x)] + c (C) (x/2)[cos(log x) - sin(log x)] + c (D) (x/2)[cos(log x) - sin(log x)] + c

int_(1) ^(pi//2) (sin(log x ) + cos (log x )) dx =

int cos(ln x)dx

int((1+Sin(log x))/(1+Cos(log x))])dx=

int sin (log x)dx=

Evaluate: int(sin(log x))/(x)dx

int sin (ln x) dx

Evaluate int (sin(log x))/(x)dx