[2x+y-5=0],[3x+2y-8=0]

Solve [2x+3y-7=0],[3x+2y-8=0]

The point of intersection of the diagonals of the rhombus formed by the lines 2x+y-5=0, x+2y+8=0, 2x+y+5=0, and x+2y-2=0 is

The area of the triangle formed by the lines 2x+y-4=0, 3x+2y-5=0, x+y+1=0 is

find x and y : 2x+3y-8=0, 3x+y-5=0

Consider the family of lines (x+y-1)+lambda(2x+3y-5)=0 and (3x+2y-4)+mu(x+2y-6)=0 Equation of a line that belongs to both the family is (A) x-2y-8=0 (B) x-2y+8=0 (C) 2x+y-8=0 (D) 2x-y-8=0

Consider the family of lines (x+y-1)+lambda(2x+3y-5)=0 and (3x+2y-4)+mu(x+2y-6)=0 Equation of a line that belongs to both the family is (A) x-2y-8=0 (B) x-2y+8=0 (C) 2x+y-8=0 (D) 2x-y-8=0

The figure formed by the lines 2x-5y+4=0, 5x+2y+7=0, 2x-5y+3=0, 5x+2y-6=0 is

The quadrilateral formed by the lines 2x-5y+7=0,5x+2y-1=0,2x-5y+2=0,5x+2y+3=0 is

Solve for x and y - 2x+3y-8=0 3x+4y-5=0

{:(3x - y - 2 - 0),(2x + y - 8 = 0):}