" Sif "y=x^(3)-x+1" at the point whose "x-" co-ordinate is "2

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Find the slope of the tangent to the curve y=x^(3)-x+1 at the point whose x co-ordinate is 2.

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The equation of normal to the curve y=x^(2)+4x at the point whose ordinate is -3, is

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Equation of normal to y^(2) = 4x at the point whose ordinate is 4 is