`f(x, y) = 0` is a circle such that `f(0, lambda) = 0 and f(lambda, 0)=0` have equal roots and `f(1, 1)= -2` then the radius of the circle is : (A) 4 (B) 8 (C) 2 (D) 1

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/5 ,5, then the radius of the circle is

Let f(x,y)=0 be the equation of circle.If f(0,lambda)=0 has equal roots lambda=1,1 and f(lambda,0)=0 has roots lambda=(1)/(5),5 ,then the radius of the circle

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/2 ,2, then the centre of the circle is

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/2 ,2, then the centre of the circle is

Suppose f(x,y)=0 is the equation of a circle such that f(x,1)=0 has equal roots (each equal to 2) and f(1,x)=0 also has equal roots (each equal to zero). The equation of circle is

Suppose f(x,y)=0 is the equation of a circle such that f(x,1)=0 has equal roots (each equal to 2) and f(1,x)=0 also has equal roots (each equal to zero). The equation of circle is

If f(x) is a quadratic expression such that f(1) + f(2) = 0, and -1 is a root of f(x) = 0 , then the other root of f(x) = 0 is :

f(x , y)=x^2+y^2+2a x+2b y+c=0 represents a circle. If f(x ,0)=0 has equal roots, each being 2, and f(0,y)=0 has 2 and 3 as its roots, then the center of the circle is

f(x , y)=x^2+y^2+2a x+2b y+c=0 represents a circle. If f(x ,0)=0 has equal roots, each being 2, and f(0,y)=0 has 2 and 3 as its roots, then the center of the circle is