In a triangle `A B C ,` if `A B=A C\ a n d\ A B` is produced to `D` such that `B D=B C ,` find `/_A C D\ :\ /_A D C`

In a A B C , if A B=A C\ a n d\ B C is produced to D such that /_A C D=100^0, then /_A= (a) 20^0 (b) 40^0 (c) 60^0 (d) 80^0

In A B C , side A B is produced to D so that B D=b cdot If /_B=60^0 and /_A=70^0, prove that : A D > C D A D > A C

In Figure, side B C\ of A B C is produced to point D such that bisectors of /_A B C\ a n d\ /_A C D meet at a point Edot If /_B A C=68^0, find /_B E C

In Figure, A B=A C\ a n d\ D B=D Cdot\ Prove that /_A B D=/_A C D

In Fig.81, side B C of A B C has been produced to D and C E B Adot If /_A B C=65^0,\ /_B A C=55^0, find /_A C E ,\ /_E C D\ a n d\ /_A C Ddot

In Fig.81, side B C of A B C has been produced to D and C E B Adot If /_A B C=65^0,\ /_B A C=55^0, find /_A C E ,\ /_E C D\ a n d\ /_A C Ddot

In A B C , side A B is produced to D so that B D=B Cdot If /_B=60^0\ a n d\ /_A=70^0, prove that: A D > C D (ii) A D > A C

In a A B C ,\ /_A=50^0a n d\ B C is produced to a point Ddot If the bisectors of /_A B C\ a n d\ /_A C D meet at E , then /_E= (a) 25^0 (b) 50^0 (c) 100^0 (d) 75^0

In Figure, A B=A C\ a n d\ /_A C D=120^0dot Find /_A

In A B C ,\ /_A=50^0\ a n d\ B C is produced to a point D. The bisectors of /_A B C\ a n d\ /_A C D meet at Edot find /_Edot