`angleA + 1/2 angleB+ angleC=140^(@)`, then `angleB` is `angleA +1/2angleB + angleC=140^(@)`, हे, तब `angleB` हे।

Find angleA+angleB+angleC+angleD

In triangleABC , if angleB=76^@ , and angleC=48^@ find angleA

In triangleABC , AB=AC and angleA=100^@ , find angleB and angleC .

DeltaABC , angleA+angleB=65^(@) , angleB+angleC=140^(@) ,then angleB is equal to

In triangleABC , if angleA=55^@ , angleB=40^@ find angleC

In triangleABC , if angleA+angleB=108^@ and angleB+angleC=109^@ , find angleA,angleB and angleC

In a triangleABC if angleA=72^(@) and angleB=63^(@) ,find angleC

The following steps are involvedd in finding the angles of the triangles ABC, when angleA: angleB: angleC=1:2:3 . Arrange them in sequential order. (A) Let the angle be angleA=x, angleB=2x and angleC=3x . (B) Given angleA: angleB: angleC=1:2:3 (C ) angleA=30^(@),angleB=2(30^(@))=60^(@) and angleC=3(30^(@))=90^(@) . (D) angleA+angleB+angleC=180^(@)implies x+2x+3x=180^(@) (E ) 6x=180^(@)impliesx=30^(@)

In a quadrilateral ABCD, angleA + angleC = 180^(@) , then angleB + angleD is equal to