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cos4x=1-8sin'n*cos^(2)...

cos4x=1-8sin'n*cos^(2)

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Prove that :cos4x=1-8sin^(2)x cos^(2)x

cos4x=1-8sin^(2)x cos^(2)x

cos4x=1-8sin^(2)x cos^(2)x

cos4x=1-8sin^(2)x cos^(2) x

If sin x+sin^(2)x+sin^(3)x=1 then cos^(6)x-4cos^(4)x+8 cos^(2)x=

If sinx + sin^(2)x + sin^(3)x = 1 , then : cos^(6)x - 4cos^(4)x + 8cos^(2)x equals :

int(sin^(8)x-cos^(8)x)/(1-2sin^(2)x cos^(2)x)dx=

int(sin^(8)x-cos^(8)x)/(1-2sin^(2)x cos^(2)x)dx

int (sin^(8)x-cos^(8)x)/(1-2sin^(2)x cos^(2)x)dx =