(1+sec theta_(0))(1+sec40)(1+sec80)

(1+ sec 20^(0))(1+sec40^(0))(1+ sec80^(0))=

The expression,(1+sec2 theta)(1+sec4 theta)(1+sec8 theta) is equal to -

Prove that: (1+sec2 theta)(1+sec4 theta)(1+sec8 theta)...(1+sec2^(n)theta)=tan2^(n)theta cot theta,n in N

Find the value of tantheta(1+sec2theta)(1+sec4theta)(1+sec8theta) .

Find the value of tantheta(1+sec2theta)(1+sec4theta)(1+sec8theta) , when theta=pi/32

Find the value of tantheta(1+sec2theta)(1+sec4theta)(1+sec8theta) , when theta=pi/32

Prove that (1+sec2theta)(1+sec4theta)(1+sec8theta)=(tan8theta)/(tantheta)

(1+sec20^(@))(1+sec40^(@))(1+sec80^(@))=

For a positive integer n f_(n)(theta)=((tan theta)/(2))(1+sec theta)(1+sec2 theta)(1+sec4 theta)...(1+sec2^(n)theta) ,then