ABC is an isosceles triangle right angled at A. forces of magnitude `2sqrt(2),5 and 6` act along BC, CA and AB respectively. The magnitude of their resultant force is

ABC is isosceles triangle, right angled at A. The resultant of the forces acting along vec(AB), vec(AC) with magnitudes 1/(AB) and 1/(AC) respectively is the force along vec(AD) , where D is the foot of the perpendicular from A on BC. The magnitude of the resultant is:

ABC is isosceles triangle, right angled at A. The resultant of the forces acting along vec(AB), vec(AC) with magnitudes 1/(AB) and 1/(AC) respectively is the force along vec(AD) , where D is the foot of the perpendicular from A on BC. The magnitude of the resultant is:

Two forces each of magnitude 2N, act at an angle of 60^(@) . What is the magnitude of the resultant force ?

ABC is a right triangle, right angled at C and AB = sqrt2 BC. Then, find angle ABC.

Three equla force, each of magnitude P, act along the side AB, BC, and CA of a trangle. Calculate the resultant force.

Two forces each of magnitude 2N, act at an angle of 60^(@) . The magnitude of the resultant force

Three vectors of magnitude 3,6 and 6 units are acting along the sides of an equilateral triangle taken in order The magnitude of their resultant is