Last two digits of 21 to the `100^(th)` power is

If the number formed by the last two digits of a three digit integer is an integral multiple of 6, the orginal integer itself will always be divisible by

The last two digits of the number 19^(9^(4)) is

The last two digit of the number (17)^(10)

Difference of last two digits of 2019^(2019^(2019)) is

The last two digits of 3^(400) is