Consider function `f: R - {-1,1}-> R`. `f(x)=x/[1-|x|]` Then the incorrect statement is

Consider function f:R-{-1,1}rarr Rf(x)=(x)/(1-|x|) Then the incorrect statement is

Consider the function f:R -{1} given by f (x)= (2x)/(x-1) Then f'(1) =

Consider the function f:R -{1} to R -{2} given by f (x) =(2x)/(x-1). Then

Draw the graph of the function f : R- {-1, 1} rarr R.f(x)=(x)/(1-|x|) .

Consider the function f(x)=|x-1|+x^(2) where x in R. Which one of the following statements is correct?

Let the function f: R to R be defined by f(x)=x^(3)-x^(2)+(x-1) sin x and "let" g: R to R be an arbitrary function Let f g: R to R be the function defined by (fg)(x)=f(x)g(x) . Then which of the folloiwng statements is/are TRUE ?

A function f: R to R is defined as f(x)=4x-1, x in R, then prove that f is one - one.