A given piece of wire of length `l` and radius r and resistance `R` is stretched uniformly to wire of radius `(r)/(2)` .Its new resistance is:

A given piece of wire oflength I, cross sectional area and resistance R is stretched uniformly to a wire oflength 21. What is the new resistance?

A uniform wire of length l and radius r has a resistance of 100 Omega . It is recast into wire of radius (R )/(2)

A uniform wire of length / and radius r has a resistance of 100 Omega . It is recast into a wire of radius (r )/(2) . The resistance of new wire will be:

A wire of radius r has resistance R. If it is stretched to a radius of (3r)/(4) , its resistance becomes

" A wire of length L and resistance "R" is stretched to get the radius of cross-section halved.What is the new resistance "

A resistance R is stretched to four times its length. Its new resistance will be

A metal resistance R is stretched to double its length. Its new resistance will be ………….. .

A wire of resistance 2Omega is stretched so that its radius is halved. Determine its new resistance.