The motion of a particle is described as `S =2-3t+4t^(3)` what is the acceleration of the paricle at the point where its velocity is zero ?

A particle is moving along a line according to the law s=t^3-3t^2+5 . The acceleration of the particle at the instant where the velocity is zero is

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

The displacement of a particle in time 't' is given by S = t^(3) - t^(2) - 8t =18 . The acceleration of the particle when its velocity vanishes is

The displacement x of a particle varies as sqrt(x)=t-2 (i) What is the velocity and acceleration of the particle at t=0? (ii) When will the velocity of the particle become zero? (iii) What is the displacement of the particle when its velocity is zero? (iv) Is the motion of the particle uniformly accelerated or not?

The displacement of a particle is described by x = t + 2t^(2) +3t^(3) -4t^(4) The acceleration at t = 3s is

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .