In the figure, the area of square `ABCD is 4 cm^2` and E any point on AB,F,H and K are the mid point of `DE,CF,DG, and CH` respectively. The area of `DeltaKDC` is -

Area of square ABCD is 4 unit^2 *M and N are mid points of AB and BC. Find PC.

In the figure given below, ABCD is a square of side 14 cm with E, F, G and H as the mid points of sides AB, BC, CD and DA respectively. The area of the shaded portion is

In the given figure ABCD is a parallelogram in which AB||CD and E and F are the mid points of AB and BC respectively. What is the area of angleBEF ?

The area of square ABCD is 16cm^(2). Find the area of the square joining the mid-point of the sides.

In the adjoining figure, D and E are the mid-points of AB and AC respectively. If DE = 4 cm , then BC is equal to :

Let ABCD be a parallelogram of area 124cm^(2). If E and F are the mid-points of sides AB and CD respectively,then find the area of parallelogram AEFD.