x=2at^(2),y=set^(4)

Solution set log_(4)x-log_(2)y=0 and x^(2)-5y^(2)+4=0 is

Show that the following set of curves intersect orthogonally: y=x^(3) and 6y=7-x^(2)x^(3)-3xy^(2)=-2 and 3x^(2)y-y=2x^(2)+4y^(2)=8 and x^(2)-2y^(2)=4

If the sets of equations z^(x)=y^(2x),2^(x)=2.4^(x),x+y+z=16, the integral roots in the order x,y,z

In the sets of equations z^(x)=y^(2x),2^(z)=2.4^(x)x+y+z=16, the integral roots in the order x, y,z are :

The shaed region represents the set C of all points (x, y) such that x^(2)+y^(2)le 1 . The transformation T maps the point (x, y) to the point (2x, 4y). Which of the following shows the mapping of the set C by the transformation T ?

What is the set of points (x,y) satisfying the equations x^(2) + y^(2) = 4 and x+ y =2 ?

If ={(x,y)|x^(2)+y^(2)<=4} and B={(x,y)|(x-3)^(2)+y^(2)<=4} and A={(x,y)|x^(2)+y^(2)<=4} and B={(x,y)|(x-3)^(2)+y^(2)<=4} and then point P(alpha,a-(1)/(2)) belongs to the set B-A then the set of possible real values of alpha is

The relation R defined on the set A = { 1, 2, 3, 4} by : R= {( x,y) : |x^(2)-y^(2)| le 10, x,y in A} is given by :

The set {(x, y)|x^(2) + y^(2) le 2} is a convex set

If R={(x,y):x,y in z,x^(2)+y^(2)<=4} is a relation defined on the set z of integers,then writedomain and range.