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" (xii) "(x)/(3)+1=(7)/(15)...

" (xii) "(x)/(3)+1=(7)/(15)

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(2x)/(3)+1=(7x)/(15)+3

(2x)/(3)-(7x)/(15)=?

Solve the equation *(x)/(3)+1=(7)/(15)

(1)4z+3=6+2z(2)(2x)/(3)+1=(7x)/(15)+3