(x+5)^(2)+(y-3)^(2)=36

Find the equation of the tangents of the hyperbola 4x ^(2) - 9y ^(2) = 36, which are parallel to the line 5x - 3y =2.

Eccentricity and latus-rectum of x^(2) - 3y^(2) = 36 are

16(x+y)^(2)-36(x-y)^(2)=

Factorize :12x^(3)y^(3)+16x^(2)y^(5)-4x^(5)y^(2)18a^(3)b^(2)+36ab^(4)-24a^(2)b^(3)

Factorize each of the following algebraic expressions: a^(2)+14a+48(2)x^(2)-4x-21y^(2)+5y-36(4)(a^(2)-5a)^(2)-36(a+7)(a-10)+16

24x ^(3) - 36x ^(2)y

Factorise: 25(x+y)^(2)- 36 (x-2y)^(2).

(9x^(2)-25y^(2)+60y-36)/((3x+5y-6))