2xy+y^(2)-2x^(2)(dy)/(dx)=0;y=2" when "x=1

2 x y+y^2-2 x^2 (dy)/(dx)=0 , y=2 when x=1

x^(2)dy+(x^(2)-xy+y^(2))dx=0

(3xy+y^(2))dx+(x^(2)+xy)dy=0

x^(2)dy+(xy + y^(2))dx = 0, y = 1 when x = 1

x^(2)dy+(xy + y^(2))dx = 0, y = 1 when x = 1

x^(2)dy+(xy + y^(2))dx = 0, y = 1 when x = 1

Solve: (1-x^2)(dy)/(dx)-xy=x^2 , given y = 2 when x= 0.

Find the particular solution of the differential equation ;(x^(2)+xy)dy=(x^(2)+y^(2))dx given that y=0 when x=1

(1 + x^(2))(dy)/(dx) + 2xy = (1)/(1 + x^(2)), y = 0 when x= 1