[" Two light waves are represented by "],[Y_(1)=a sin omega t" and "Y_(2)=a sin(omega t+delta)" .The phase of he "],[" resultant wave is "]

Two light waves are represented by y_(1)=a sin_(omega)t and y_(2)= a sin(omega t+delta) . The phase of the resultant wave is

Two wave are represented by equation y_(1) = a sin omega t and y_(2) = a cos omega t the first wave :-

Two waves are represented by the equations y_1=a sin omega t and y_2=a cos omegat . The first wave

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

The displacement of two interfering light waves are y_(1)=4 sin omega t" and "y_(2)= 3 cos (omega t) . The amplitude of the resultant waves is (y_(1)" and "y_(2) are in CGS system)

Equations of two light waves are y_(1) = 4 sin omega t and y_(2) = 3 sin (omega t + (pi)/(2)) . What is the amplitude of the resultant wave as they superpose on each other?

Two waves are given by y_(1) = a sin (omega t - kx) and y_(2) = a cos (omega t - kx) . The phase difference between the two waves is