" (iii) "sec120^(@)

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Prove that : sec alpha+ sec (120^(@)+ alpha) sec (120^(@)-alpha)=-3 sec 3 alpha

The value of sec 40^(@)+sec 80^(@)+sec 160^(@) will be

cos A + cos (120 ^(@) - A ) + cos (120 ^(@) + A ) =0

The period of sin x sin(120^(@) + x) sin(120^(@) -x) is

" cos x + cos " (120^(@) -x ) + " cos "(120^(@) +x)=0

The minimum of cos^(2)(120^(@) + x)+ cos^(2) (120^(@) -x) is

(cos (45 ^ (@) + A) -cos (45 ^ (@) - A)) / (sin (120 ^ (@) + A) -sin (120 ^ (@) - A)) =

cos theta + cos (120^(@) + theta ) + cos (120^(@) - theta )=

( cos (45^(@) + A) - cos (45^(@) - A))/( sin (120^(@) + A)-sin(120^@-A))=