" 16."x(1+2x)^(2)

The eccentricity of the hyperbola 16x^(2)-9y^(2)=1 is The eccentricity of the hyperbola 16x^(2)-9y^(2)=1 is

Find the integral of (1)/(x^(2)-a^(2)) with respectto x and hence evaluate int (1)/(x^(2)-16)dx

Factorize 16x^(2) + (1)/(16x^(2)) -2

If x^(4)/((x-1)(x+2))=1/(3(x-1))-16/(3(x+2))+x^(2)-x+k , then k =

If sec theta= 8x and tan theta= 8/x, (x ne 0) then the value of 16(x^2-1/x^2) is:

If sec theta= 8x and tan theta=8/x (x ne 0) , then the value of 16(x^2-1/x^2) is: यदि sec theta=8x तथा tan theta= 8/x (x ne 0) है, तो 16(x^2-1/x^2) का मान क्या होगा ?

Assuming 'x' to be small that x^(2) and higher power of x' can be neglected,show that,(1+(3)/(4)(x))^(-4)(16-3x)^((1)/(2))(8+x)^(2) appoximately equat to,1-(305)/(96)x

Assuming x to be so small that x^(2) and higher power of x can be neglected,prove that ((1+(3x)/(4))^(-4)(16-3x)^((1)/(2)))/((8+x)^((2)/(3)))=1-((305)/(96))x

If x_(1),x_(2)….x_(10) are 10 observations, in which mean of x_(1),x_(2),x_(3),x_(4) is 11 while mean of x_(5),x_(6)….x_(10) is 16. also x_(1)^(2)+x_(2)^(2)+….x_(10)^(2)=2000 then value of standard devition is