If `alpha = cos theta+i sin theta,`then `(1+alpha)/(1-alpha)` equals (i)`cottheta` (ii)`itan(theta/2)` (iii)`icot(theta/2)` (iv) `cot(theta/2)`

If a=cos theta+i sin theta, then (1+a)/(1-a) is equal to ( i) cot((theta)/(2))( ii) cot theta( iii) i cot((theta)/(2))( iv )i tan((theta)/(2))

If a=costheta+isintheta, then (1+a)/(1-a) is: (a) . cot(theta/2) (b) . cottheta (c) . icot(theta/2) (d) . itan(theta/2)

If cos theta=cos alpha cos beta then tan((theta+alpha)/2) tan((theta-alpha)/2)= (i) tan^2(alpha/2) (ii) tan^2(beta/2) (iii) tan^2(theta/2) (iv) cot^2(beta/2)

If cos(theta+2 alpha)=m cos theta, show that cot alpha=(1+m)/(1-m)tan(theta+alpha)

If cos theta=cos alpha cos beta then tan((theta+alpha)/(2))tan((theta-alpha)/(2))=(i)tan^(2)((alpha)/(2))(ii)tan^(2)((beta)/(2))( iii)tan ^(2)((theta)/(2))(iv)cot^(2)((beta)/(2))

If 1+sin theta=9cos theta and 0^(@)

If : cos 2 theta = sin alpha , then : theta is given by

Evaluate int (cos 2 theta - cos 2 alpha )/(sin alpha - sin theta ) d theta