" If "tan(A-B)=(7)/(24),tan A=(4)/(3)" where "A,B" acute then "A+B=

If tan (A-B)=7//24 , tan A=4//3 " where " A,B are acute , then A+B=

If tan A=(1)/(3), tan B=(2)/(7) then cot (A+B)=

If tan A = (1)/(2), tan B = (1)/(3)and A , B are acute angles then find (A + B)

If tan (a+b)=(7)/(3) and tan b=(2)/(3) and a b are acute,then tan(b-a)=(p)/(q) when p,q in N,find the least value of (p+q)/(20)

If Tan A = (4)/(3), Tan B = (1)/(7) then A - B =

Let "sin"(A+B)=sqrt(3)/(2)and"cos"B=sqrt(3)/(2) , where A, B are acute angles. What is "tan"(2A-B) equal to ?

If A=tan^(-1)(1/7) and B=tan^(-1)(1/3) then A+B=

If tan A=(1)/(3 ) and tan B=(2)/(7) , then cot (A-B)=

If A+B, A are acute angles such that sin (A+B)=(24)/(25) and tan A=(3)/(4) , then find the value of cos B .