" (ii) "tan theta=(sin theta)/(sqrt(1-sin^(2)theta))

tan theta= A) (sqrt(1-sin^(2)theta))/(sin theta) , B) (1)/(sec theta) , C) (sin theta)/(sqrt(1-sin^(2)theta)) D) (1)/(sqrt(1+Cot^(2)theta)

If (sin^(3)theta-cos^(3)theta)/(sin theta-cos theta)-(cos theta)/(sqrt(1+cot^(2)theta))-2 tan theta cot theta=-1 (AA theta in[0, 2pi], then

If (sin^(3)theta-cos^(3)theta)/(sin theta-cos theta)-(cos theta)/(sqrt(1+cot^(2)theta))-2 tan theta cot theta=-1 (AA theta in[0, 2pi], then

(sin^(3)theta-cos^(3)theta)/(sin theta-cos theta)-(cos theta)/(sqrt(1+cot^(2)theta))-2tan theta*cot theta=-1

(sin^(3)theta-cos^(3)theta)/(sin theta-cos theta)-(cos theta)/(sqrt(1+cot^(2)theta))-2tan theta cot theta=-1

prove that sin theta + tan theta = (cos theta) / (1-sin theta)

tan(45^(@)+(1)/(2)theta)=sqrt((1+sin theta)/(1-sin theta))

sqrt((1+sin theta)/(1-sin theta))+sqrt((1-sin theta)/(1+sin theta))=2sec theta

(sin ^(3) theta - cos^(3) theta)/(sin theta - cos theta) - (cos theta)/(sqrt(1 + cot^(2)theta))-2 tan theta cot theta = - 1 , if

(tan theta+sec theta-1)(tan theta+1+sec theta)=(2sin theta)/(1-sin theta)