" Find EAN value of "Mg" in "[Mg(EDTA)]^(2-)

Give EAN value of Mg in [Mg(EDTA)]^(2-) .

Give EAN value of Mg in [Mg(EDTA)]^(2-) .

EAN of mg is …… in [Mg(EDTA ) ]^(2-)

The number of oxygen atoms involved in bonding in the coordination sphere of [Mg(EDTA)]^(2-) is

1g of magnesium vapor absorbs 50 kJ of light enegry. Find the percentage of Mg^(+)(g) and Mg^(2+)(g) in the vapor if Delta_(i)H_(1) = 738kJ mol^(-1) and Delta_(i)H_(2) = 1450kJmol^(-1) . Strategy: Find the number of moles of Mg atoms present in 1g of Mg vapor. Find the moles of Mg^(+) and Mg^(2+) formed by absorbing enegry. Use the following ratio of calculate the percentage of Mg^(+)(g) : %Mg^(+)(g) = (n_(Mg^(+(g))))/(n_(Mg^((g))))xx100% Finally, % Mg^(2+) = 100% - % Mg^(+)(g)

E^@ (red.) values of the half cells Mg^(2+)//Mg and Cl_2//Cl^- are respectively -2.36V and +1.36V . The E^@ values of the cell Mg|Mg^(2+)||Cl_2|Cl^- is

Calculate the energy required to convert all atoms of Mg to Mg^(2+) ions present in 48 mg of Mg vapours. IE_(1) and IE_(2) of Mg are 740 and 1450 kJ mol^(-1) respectively.

Find the e.m.f. of the cell, Mg(s)//Mg^(2+)(0.01 M) || Cu^(2+)(aq)(0.0001 M)//Cu(s) "Given" E_(Mg^(2+)//Mg)^(@)=-2.37 " volts" , E_(Cu^(2+)//Cu)^(@)=+0.34" volts" .