" (iv) "5z^(2)-16z-21

Simplify (4yz (z ^ (2) + 16z-16)) / (2y (z-8))

If z=1+2i , show that z^(2)-2z+5=0 . Hence find the value of z^(3) +7z^(2)-z+16 .

If z=1+2i , show that z^(2)-2z+5=0 . Hence find the value of z^(3) +7z^(2)-z+16 .

Factorise 8z^(2) - 16z + 48

The point of translation to remove the first degree terms from the equation 5x^(2)-2y^(2)+z^(2)-10x-8y-16z-7=0 is

If x,y,z are real and 4x^(2)+9y^(2)+16z^(2)=2xyz{(6)/(x)+(4)/(y)+(3)/(z)}

Let z_(1), z_(2), z_(3) be the roots of iz^(3) + 5z^(2) - z + 5i = 0 , then |z_(1)| + |z_(2)| + |z_(3)| = _____________.

If x,y,z are real and 4x^(2) +9y^(2)+16z^(2) -6xy-12yz-8zx =0 then x,y,z are in

Work out the division: z(5z^(2)-80)-:5z(z+4)