" question: "quad " If "y=ax^(n+1)+bx^(-n)" and "x^(2)(d^(2)y)/(dx^(2))=lambda y," then write the value of "lambda

If y = ax^(n+1) + bx^(-1) , then x^(2) (d^(2)y)/(dx^(2)) =

If y=2^(n+1)+(3)/(x^(n)) , then x^(2)(d^(2)y)/(dx^(2)) is

if y^(2)=ax^(2)+2bx+c then y^(3)(d^(2)y)/(dx^(2))

If y = ax^(n+1)+bx^(n+1) then x^2(d^2y)/(dx^2) is equal to

If y=ax^(n+1)+bx^(-n), then x^(2)(d^(2)y)/(dx^(2))=n(n-1)y(b)n(n+1)y(c)ny(d)n^(2)y

If y=ax^(n+1)+bx^(-n), then x^(2)(d^(2)y)/(dx^(2)) is equal to n(n-1)y(b)n(n+1)yny(d)n^(2)y

By eliminating the constant in the following equation x^(2)-y^(2)=c(x^(2)+y^(2))^(2) its differential equation is y'=(x(lambda y^(2)-x^(2)))/(y(lambda x^(2)-y^(2))) then find the value of lambda

y = e^(ax) then (d^(n)y)/(dx^(n)) = y_(n) is: