If poitns `A(3,5)` and B are equidistant from `H(sqrt2,sqrt5)` and B has rational coordinates,then `AB=`

Rationalize 3/(2sqrt7+sqrt5)

Rationalize the denominator of 5/(sqrt3-sqrt5)

If (4+3sqrt5)/(4-3sqrt5)=a+bsqrt5 ,a, b are rational numbers, them (a, b)=

If (4+3sqrt5)/(4-3sqrt5)=a+bsqrt5 ,a, b are rational numbers, them (a, b)=

Express (3)/(sqrt(3) - sqrt(2) + sqrt(5)) with rational denominator.

Rationalize : ( sqrt(2) + sqrt(3) ) / sqrt(5)

If both 'a' and 'b' are rational numbers, then 'a' and 'b' from (3-sqrt(5))/(3+2sqrt(5))=asqrt(5)-b , respectively are

rationalize 3/(sqrt3+sqrt5-sqrt2)

Let n be the number of points having rational coordinates equidistant from the point (0,sqrt3) , then

In ABC, the coordinates of B are (0,0),AB=2,/_ABC=(pi)/(3), and the middle point of BC has coordinates (2,0) .The centroid o the triangle is ((1)/(2),(sqrt(3))/(2))(b)((5)/(3),(1)/(sqrt(3)))(4+(sqrt(3))/(3),(1)/(3))( d) none of these