(wij)n(x+5)(x+7)(x+12)=-150

Evaluate the following limit: (lim)_(x->5)(x^2-7x+12)/(x^2-3x-4)

Solve the following: (x^2 -5x+12)/(5x-12) = (x^2 -x-4)/(x+4)

x^(5).y^(7)=(x+y)^(12)

The value of x for which ((7)/(12)) ^(-4) xx ((7)/(12))^(3x) = ((7)/(12))^(5) is

Solve for x : (3x -2)/(5x + 7) = (1)/(12)

sqrt(3+x)+sqrt(3-x)sqrt(3+x)-sqrt(3-x)(5)/(7)( b) (7)/(5)(c)(5)/(12) (d) (12)/(5)

If (x + 4), (x + 12), (x - 1), and (x + 5) are in proportion then the mean proportional between x and (x - 7)is:

(12x + 17) / (3x + 1)-(2x + 15) / (x + 7) = 3 (1) / (5), x! =-(1) / (3), -7