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[(sin theta)/(sin(90^(@)-theta))+(cos th...

[(sin theta)/(sin(90^(@)-theta))+(cos theta)/(cos(90^(@)-theta))],[=sec(90^(@)-theta)cosec(90^(@)-theta)]

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Without using trigonometrical tables; prove (sin theta)/(sin(90-theta))+(cos theta)/(cos(90^(@)-theta))=sec theta*cosec theta

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