A line `AB` is of length 5. `A` is the point `(2,-3)` .If the abscissa of the point `B` is 5" prove that the ordinate of `B` is 1 or -7

The length of a line segment is 10 units . If the coordinates of its one end point are (2,-3) and the abscissa of the other end point is 10, then its ordinate is . . . . .

See fig and Write the following : (i) The coordinates of B (ii) The coordinates of C (iii) The point identified by the coordinates (-3,-5) (iv) The point identified by the coordinates (2,-4) (v) The abscissa of the point D . (vi) The ordinates of the point H . (vii) The co-ordinates of the point L . (viii) The co-ordinates of the point M .

The co-ordinates of the mid-point of line joining the points A and B are (2, -3). If the co-ordinates of point A are (-3, 4), then find the co- ordinates of point B.

The co-ordinates of the mid-point of line joining the points A and B are (2, -3). If the co-ordinates of point A are (-3, 4), then find the co- ordinates of point B.

A is a point on the x-axis with abscissa -8 and B is a point on the y-axis with ordinate 15. Find the distance AB.

A point whose abscissa is -3\ and ordinate 2 lies in

A point P is equidistant from A (3, 1) and B (5, 3) and its abscissa is twice its ordinate, then its co-ordinates are.

The abscissa of point A is equal to its ordinate, and its distance from the point B(1,3) is 10 units, What are the coordinates of A?

[ A-2.The coordinates of a point are (0,1) and the ordinate of another point is -3. If the distance between the two point is 5 then the abscissa of another point is- [ (1) -3, (2) 3, (3) +-3, (4) 1]]