`dy/dx +xy= x^3y^3`

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Solve the differential equation: (1+x^(2))(dy)/(dx)+xy=-x^(3)y^(3)

(dy)/(dx)+xy=xy^(3)

Solve (dy)/(dx)+xy=xy^(3)

(dy)/(dx)=x^(3)y^(3)-xy

Solve: (dy)/(dx)=x^3y^3-xy

FInd (dy)/(dx) if xy^(3)-yx^(3)=x

(dy)/(dx)+2xy=x^(3)

Solve (dy)/(dx)=(x^(2)+3y^(2))/(2xy)

dy/dx + 2xy - x = 0, y(0) = 3.