Evaluate `int_0^(2pi) sin^2x cos^4x dx=`

int_0^pi sin^4x cos^4x dx

Evaluate int_0^(pi/2) cos^2x dx

Evaluate (i) int_0^(pi//4) sin x cos x dx (ii) int_0^(pi//2) (1 + cos x)^(1//2) dx (iii) int_0^(pi//2) (1 + sin x)^(1//2) dx (iv) int_0^(pi//4) (1 -cos 2x)^(1//2)dx

int_(0)^( pi/2)sin^(2)x cos x dx

Evaluate: int_0^pi cos 2x log sin x dx

Evaluate: int_0^(pi//4)(sin\ 2x)/(cos^4x+sin^4x)dx

Evaluate: int_0^(pi//2)1/(4sin^2x+5cos^2x)dx

If int_(0)^(pi//2)sin^(4)x cos^(2)x dx=(pi)/(32) , then int_(0)^(pi//2)sin^(2)x cos^(4)x dx=

Evaluate int_0^(pi//2)(sin^2xdotcos^2x)/((sin^3x+cos^3x)^2)dx

Evaluate: int_0^(pi//2)cos^2x\ dx